In a 49 s interval, 595 hailstones strike a glass window of an area of 0.954 m at an angle of 25° to the window surface. Each hailstone has a mass of 7 g and a speed of 4.5 m/s. If the collisions are elastic, what is the average force on the window?

Respuesta :

Average  force on the window: 0.32 N

Explanation:

The average force exerted on the window is given by Newton's second law

[tex]F=\frac{\Delta p}{\Delta t}[/tex]

where

[tex]\Delta p[/tex] is the net change in momentum of the hailstones in a time interval of [tex]\Delta t[/tex]

In order to find the change in momentum, we have to consider only the component of the hailstone's momentum perpendicular to the window, therefore:

[tex]p_i =m u sin \theta[/tex] is the initial momentum of one hailstone, with

m = 7 g = 0.007 kg is the mass

[tex]u=4.5 m/s[/tex] is the initial speed

[tex]\theta=25^{\circ}[/tex] is the angle with the window

The final momentum is

[tex]p_f = mv sin \theta[/tex]

where

v = 4.5 m/s is the final speed (the  collision is elastic so the speed is equal, while the direction changes)

[tex]\theta=-25^{\circ}[/tex] (after the rebound, the direction has changed)

So the change in momentum of 1 hailstone is

[tex]\Delta p = mv sin(-25^{\circ})-mu sin(25^{\circ})=-2mu sin(25^{\circ})=-0.0266 kg m/s[/tex]

We are interested only in the magnitude, so

[tex]\Delta p = 0.0266 kg m/s[/tex]

There are 595 hailstones hitting the window in 49 s, so the total change in momentum is

[tex]\Delta p = 595\cdot 0.0266 = 15.8 kg m/s[/tex]

And therefore, the average force on the window is

[tex]F=\frac{\Delta p}{\Delta t}=\frac{15.8}{49}=0.32 N[/tex]

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The average force on the window is 0.323N

Elastic collision:

Since the collision is elasctic the hailstone bounces back with the same velocity.

Therefore the change in momentum of the hailstone is:

Δp = 2 × mass × velocity

But the hailstone is inclined at an angle 25° so

For one hailstone we have;

Δp = 2×0.007×4.5×sin25

Δp = 0.0266 kgm/s

For 595 hailstones

ΔP = 595 × 0.0266

ΔP = 15.82 kgm/s

Now the average force is the rate of change of momentum:

F = ΔP/Δt

F = 15.82/49

F = 0.323N

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