Respuesta :
Answer:
Only Mn⁺² is present.
Explanation:
- When an aqueous solution of NaCl is added, the Cl⁻ species is introduced. In the presence of Cl⁻, Hg₂²⁺ would precipitate as Hg₂Cl₂.
- When an aqueous solution of Na₂SO₄ is added, the SO₄⁻² species is introduced. In the presence of SO₄⁻², Ba⁺² would precipitate as BaSO₄.
No precipitate formed when either of these solutions were added, thus the sample does not contain Hg₂⁺² nor Ba⁺².
- Under basic conditions Mn⁺² would precipitate as Mn(OH)₂. A precipitate formed once the solution was made basic, so the sample contains Mn⁺².
[tex]\rm Mn_2^\;+[/tex] ion or ions are present in the sample solution.
What is a precipitate?
A precipitate is usually a crystalline solid substance that is separated from a solution.
The [tex]SO_4[/tex] species is introduced when an aqueous phase of Na2SO4 is added. Ba+2 would precipitate as BaSO4 in the presence of [tex]SO_4.[/tex].
[tex]\rm Mn_2^\;+[/tex]would precipitate as Mn(OH)2 under basic circumstances. When the solution was turned basic, a precipitate formed, and the sample now contains [tex]\rm Mn_2^\;+[/tex].
Thus, the ion present in the solution is [tex]\rm Mn_2^\;+[/tex].
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