In the Dominican Republic in August, the distribution of daily high temperature is approximately normal with mean 86 degrees Fahrenheit ( °F °F ). Approximately 95% of all daily high temperatures are between 83°F 83°F and 89°F 89°F . What is the standard deviation of the distribution?

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Answer:

The standard deviation is 1.5

Explanation:

Use the z-score formula to find the standard deviation.

[tex]z = \frac{x - \mu}{ \sigma} [/tex]

Using the empirical rule 95% falls within 2 standard deviations of the mean.

Using the upper limit, we have x=89 and

[tex] \mu = 86[/tex]

We substitute and solve for the standard deviation.

[tex]2= \frac{89- 86}{ \sigma} [/tex]

This means

[tex]\sigma= \frac{89- 86}{ 2} = \frac{3}{2} [/tex]

[tex]\sigma = 1.5[/tex]

The standard deviation of the distribution in the Dominican Republic in August is 1.53

The distribution represents a normal distribution

The mean temperature is:

[tex]\mu = 86^0F[/tex]

Approximately 95% of all daily high temperatures are between 83°F and 89°F

That is:

[tex]X_1 = 83^oF\\\\X_2 = 89^0F[/tex]

For 95% confidence interval, the z-value = 1.960

The equation showing the relationship between the z-value, the mean μ, the value of X, and the standard deviation σ is shown below:

[tex]z = \frac{X_2-\mu}{\sigma}[/tex]

Substitute X₂ = 89, μ = 86, and z = 1.960 into the equation above to solve for σ

[tex]1.96 = \frac{89-86}{\sigma} \\\\1.96 \sigma = 3\\\\\sigma = \frac{3}{1.96} \\\\\sigma = 1.53[/tex]

The standard deviation of the distribution is 1.53

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