Answer:(E) The margin of error for R will be 2 times the margin of error for S.
Explanation: Apply the standard error formula which is [tex]\sqrt{\frac{p(1-p)}{n} }[/tex]. Use .5 for p. Do it for sample S and sample R. The SE for S is 0.007906. The SE for R is 0.015811. 0.015811/0.007906=2. Since R is the smaller sample, it will have a higher margin of error. Thus, it is 2 times that of S. Mr. Crane.