The minimum energy required to break the oxygen-oxygen bond in oxygen is 495 kJ/mol. What is the longest wavelength of radiation that possesses the necessary energy to break this bond? What type of electromagnetic radiation is this?

Respuesta :

Answer:

241 nm, it is UV light range

Explanation:

The minimum energy needed required to break the oxygen-oxygen bond = 495 kJ/mol

Energy needed for 1 molecule of oxygen = 495 × 10³ J / avogadro's constant = 495 × 10³ J  / ( 6.02 × 10²³) = 8.223 × 10⁻¹⁹ J

Energy = hv

where h = Planck constant = 6.626 × 10 ⁻³⁴ m²kg/s and v = frequency

c speed of light = vλ

c / λ = v

E = hc / λ

λ  = hc / E = (6.626 × 10 ⁻³⁴ m²kg/s × 3.0 × 10 ⁸ m/s) / (8.223 × 10⁻¹⁹ J)  = 2.41 × 10⁻⁷m = 241 nm

UV light wavelength is between 400 nm - 10 nm

241 nm is required which corresponds to ultraviolet radiation.

Energy of the photon = 495 × 10^3 J/mol/6.02  × 10^23mol-1 = 8.22  × 10^-19 J

We know that;

E = hc/λ

h = Plank's constant = 6.6 × 10^-34 Js

c = speed of light = 3  × 10^8 m/s

λ = wavelength = ?

Now;

λ = hc/E

λ = 6.6 × 10^-34  × 3  × 10^8/ 8.22  × 10^-19

λ =  2.41 × 10^-7 or 241 nm

This corresponds to ultraviolet radiation.

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