A survey of dance club goers found that 35% of club goers prefer trance music, 25% prefer dubstep and 15% preferred both trance and dubstep. What percent of students don't prefer either trance nor dubstep

Respuesta :

Answer:

55% of students don't prefer either trance nor dubstep.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a club goer prefers trance music.

B is the probability that a club goer prefers dubstep.

C is the probability that a club goer does not like any of these.

We have that:

[tex]A = a + (A \cap B)[/tex]

In which a is the probability that a club goer likes trance music and not dubtep and [tex]A \cap B[/tex] is the probability that a club goer likes both of these styles

By the same logic, we have that:

[tex]B = b + (A \cap B)[/tex]

Either a person likes at least one these styles, or they prefer other styles. The sum of these probabilities is decimal 1. So:

[tex]P(A \cup B) + C = 1[/tex]

We want to find C to solve this question. So

[tex]C = 1 - P(A \cup B)[/tex]

In which

[tex]P(A \cup B) = a + b + (A \cap B)[/tex]

15% preferred both trance and dubstep

This means that [tex]A \cap B = 0.15[/tex]

25% prefer dubstep

This means that [tex]B = 0.25[/tex]

[tex]B = b + (A \cap B)[/tex]

[tex]0.25 = b + 0.15[/tex]

[tex]b = 0.10[/tex]

35% of club goers prefer trance music

[tex]A = a + (A \cap B)[/tex]

[tex]0.35 = a + 0.15[/tex]

[tex]a = 0.20[/tex]

What percent of students don't prefer either trance nor dubstep

[tex]P(A \cup B) = a + b + (A \cap B) = 0.20 + 0.10 + 0.15 = 0.45[/tex]

[tex]C = 1 - P(A \cup B) = 1-0.45 = 0.55[/tex]

55% of students don't prefer either trance nor dubstep.