Option C
The distance of a spin of one full rotation is 31.4 feet
Solution:
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
The circumference of circle is given as:
[tex]C = 2 \pi r[/tex]
Where "r" is the radius
[tex]C = 2 \times 3.14 \times 5\\\\C = 6.28 \times 5\\\\C = 31.4[/tex]
Thus the distance of a spin of one full rotation is 31.4 feet
