Answer:
[tex]16272 J/C[/tex]
Step-by-step explanation:
Parameters given:
Diameter of sphere = 1cm
Radius of sphere = 0.5cm = 0.005m
Charge of sphere = 45.2 pC = [tex]4.52 * 10^{-11} C[/tex]
Electric potential at a distance, r, from a charge, Q, is given as
[tex]V = \frac{kQ}{r}[/tex]
where
k = Coulombs constant
The charge of a sphere is always located at the center of the sphere. This means that the distance between the charge of the sphere and its surface is the radius.
Hence, Electric potential is:
[tex]V = \frac{9 * 10^9 * 4.52 * 10^{-11}}{0.005^2} \\\\\\V = \frac{0.4068}{0.000025}\\ \\\\V = 16272 J/C[/tex]
