Respuesta :
Answer:
The partial pressure for pentane = 20 mmHg
The partial pressure for oxygen = 160 mmHg
The pressure of the water vapor(H₂O mmHg) after reaction = 120 mmHg
Explanation:
The balanced equation for the reaction is written below as;
[tex]C_5H_{12}_{(g)}+8O_{2(g)}[/tex] ⇒ [tex]5CO_{2(g)}+6H_2O_{(g)}[/tex]
Given that;
The total pressure [tex](P_{Total})[/tex]= 180 mmHg
From the equation above; we can see that;
the numbers of moles of [tex]C_5H_{12}_{(g)[/tex] i.e [tex](M_C__5}_H__1_2}__(_g_)})[/tex] = 1
the numbers of moles of [tex]O_2[/tex] i.e [tex](M_O__2})[/tex]
∴ Using the formula for Dalton Law of Partial Pressure;
The partial pressure for pentane can be calculated as:
[tex]P_C__5}_H__{12}[/tex] = [tex](\frac{M_C_5_H_1_2}{M_C_5_H_1_2+M_O__2}}) *P_{Total}[/tex]
= [tex]\frac{1}{8+1}(180)[/tex]
= 0.1111 × (180)mmHg
= 19.98 mmHg
≅ 20 mm Hg
The partial pressure for oxygen can be calculated as:
[tex]P_O___2}[/tex] = [tex](\frac{M_O__2}{M_C_5_H_1_2+M_O__2}}) *P_{Total}[/tex]
= [tex]\frac{8}{1+8} (180)[/tex]
= 0.889 * (180) mmHg
= 160 mmHg
If the temperature and volume do not change, what is the pressure of the water vapor ( mm Hg) after reaction?
NOW, From the equation above, After the reaction is complete;
5 moles of CO₂ and 6 moles of H₂O were produced.
[tex]C_5H_{12}_{(g)}+8O_{2(g)}[/tex] ⇒ [tex]5CO_{2(g)}+6H_2O_{(g)}[/tex]
Initial (mmHg) 20 160 0 0
change -20 -8 (20) 5 (20) 6(20)
Equilibrium (mmHg) 0 0 100 120
[tex]P_{Total}[/tex] [tex]= P_C_O__2}+P_H__2O[/tex]
= (100 + 120) mmHg
=220 mmHg
numbers of moles of CO₂ = 5 moles
numbers of moles of H₂O = 6 moles
∴ To calculate the pressure of water vapor ( H₂O ) using Dalton's Law; we have;
[tex]P_H___2}O}[/tex] [tex]= (\frac{M_H__2_O}{M_H__2_O+M_C_O__2}}}) *P_{Total}[/tex]
[tex]= (\frac{5}{5+6}}}) *220[/tex]
= 0.5454 (220) mmHg
= 119.98 mmHg
≅ 120 mmHg
∴ the pressure of the water vapor(H₂O mmHg) after reaction = 120 mmHg
The Pentane gas reaction.
As per the question, the pentane reads wot the oxygen gas and gives way to the carbon dioxide gas and water vapors. If we mix the gas with oxygen then its correct stoichiometric ratio is about the mixture of 180 mm Hg and partial pressure of the pentene hence the.
Answer of partial pressure is 20 mmHg and that of oxygen is 160 mmHg.
As pentane is a sought chain of alkali and is made of 5 carbon atoms it has a role of the non polar solvents. Act's a clear colorless liquid.
The partial pressure of the gas will be 20 and reaction with water will produce a 120 mmHg.
Find out more information about the Pentane gas.
brainly.com/question/1691047.
