Explanation:
Formula depicting relation between total flux and total charge Q is as follows.
[tex]\phi = \frac{Q}{\epsilon_{o}}[/tex] (Gauss's Law)
Putting the given values into the above formula as follows.
Q = [tex]\phi \times \epsilon_{o}[/tex]
= [tex]-953 Nm^{2}/C \times 8.854 \times 10^{-12}[/tex]
= [tex]-8.4 \times 10^{-9} C[/tex]
= -8.4 nC
Therefore, when the unknown charge is q then,
-14.0 nC + 33.0 nC + q = -8.4 nC
q = -27.4 nC
Thus, we can conclude that charge on the third object is -27.4 nC.
