Answer:
Step-by-step explanation:
Vertices are A(-3,0) B (2,1) and C(3,-3)
We can find lengths of sides using distance formla
AB = [tex]\sqrt{(-3-2)^2+(0-1)^2} \\=\sqrt{26} \\=5.1[/tex]
BC= [tex]\sqrt{(2-3)^2+(1-(-3))^2} \\=\sqrt{17} \\=4.12\\[/tex]
CA = [tex]\sqrt{(-3-3)^2+(0-(-3))^2} \\=\sqrt{45} \\=6.71[/tex]
Angles are found out using cosine formula for triangles
[tex]a^2=b^2+c^2-2bc cosA\\A = arc cos \frac{6.71^2+5.1^2-4.12^2}{2*6.71*5.1} \\=37 deg 53'[/tex]
similarly
B = 92 deg 43 mint
C = 49 deg 24 minutes
