Answer:
diameter of the pipe required = 0.49 ft
Explanation:
Thinking process:
The basic step requires a knowledge of the Bernoulli's equation for fluid motion. This is a continuity equation that has an energy balance and mass balance.
P1/p + z1 + v2/2g = P2/p + z2 + V2/2G + Minor losses
The minor losses are given as follows:
f(l/D) (V2/2g)
in addition:
V = [tex]\frac{Q}{A}[/tex]
= [tex]\frac{3}{0.25*22/7D2}[/tex]
= 3.82/D²
the equation becomes
D = 1.18 f(exp 1.5)
To find the pipe diameter, a trial and error method is applied using these properties:
Re = 5.87 × 10 ⁵
D = 0.540 H
f = 0.02
This gives
D = 0.491
using the Moody chart for correlations, the diameter can be evaluated as 0.492 ft
