Answer:
[tex]y = A sin(2\pi(\dfrac{x}{50})+ 8 t)[/tex]
Explanation:
given,
wavelength, λ = 50 cm
speed, v = 4 m/s
Amplitude, A = 5 cm
general equation of the wave along x- axis
[tex]y = A sin(2\pi(\dfrac{x}{\lambda})\pm \nu t)[/tex]
sign is positive when wave is traveling in negative direction
now,
[tex]\nu = \dfrac{v}{\lambda}[/tex]
[tex]\nu = \dfrac{4}{0.5}[/tex]
[tex]\nu = 8\ s^{-1}[/tex]
inserting all the values
[tex]y = A sin(2\pi(\dfrac{x}{50})+ 8 t)[/tex]
Hence, the y-equation of wave is equal to [tex]y = A sin(2\pi(\dfrac{x}{50})+ 8 t)[/tex]
