Answer:
0.25 L (√(T/2μ)
Explanation:
Process
Let's say we have the following data set:
f = f₁
and let's assume that the length of the string is halved, which gives L₁ = 0.5 L
Suppose the tension is halved, so the tension is 0.5 T
Substituting in Fn = (n/2L)×(√T/μ)
= (1/2×0.5L) (√0.5×T/μ)
= 0.25 L (√(T/2μ)
In general, v/2 = 0.25 L (√(T/2μ)
v = 0.5 L (√(T/2μ)
As we can see, the tension is always being halved.
