Answer:
46.08 inches
Step-by-step explanation:
2.5 pounds weight stretches a spring to 18 inches
A pound weight will stretch 18inches divided by 2.5 pounds
= 7.2 inches
6.4 pounds will stretch = 7.2 X 6.4
= 46.08 inches
The spring stretch for a weight of 6.4 pounds is 46.08 inches.
Hooke's Law states that as spring is extended, the force exerted is proportional to the increase in length from the equilibrium length. The spring constant may be computed as follows:
k = -F/x,
where k is the spring constant. F represents the force, while x represents the change in spring length.
Penny attaches a weight of 2.5 pounds to a spring, and it stretches 18 inches. Therefore, the value of the spring constant can be written as,
k = -2.5 pounds / 18 inches
Now, the spring stretch for a weight of 6.4 pounds is,
k = -F/x
-2.5 pounds /18 inches = -6.4 pounds/ x inches
x = 46.08 inches
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