The maximum speed on the string will be "5.03 m/s".
Simple harmonic motion:
Given values:
- Speed, v = 24 m/s
- Wavelength, λ = 30 cm or, 0.3 m
- Amplitude, A = 1.0 cm or, 0.01 m
The velocity of wave be:
→ [tex]v = n \lambda[/tex]
or,
→ [tex]n = \frac{v}{\lambda}[/tex]
[tex]= \frac{24}{0.3}[/tex]
[tex]= 80[/tex]
Now,
→ [tex]\omega = 2 \pi n[/tex]
By substituting the values,
[tex]= 2 \pi\times 80[/tex]
[tex]= 502.86 \ rad/s[/tex]
hence,
The Maximum speed be:
= [tex]\omega t[/tex]
= [tex]502.86\times 0.01[/tex]
= [tex]5.03 \ m/s[/tex]
Thus the answer above is right.
Find out more information about harmonic motion here:
https://brainly.com/question/17315536
