The normal force is 600 N. Find the Free-body diagram in attachment
Explanation:
In this problem, there are two forces acting on the person standing on the scale on the elevator, as shown in the free body diagram in attachment (please rotate the figure 90 degrees clockwise):
- The weight of the person, [tex]W=600 N[/tex], which acts downward
- The normal force exerted by the scale on the person, N, acting upward
The magnitude of the normal force corresponds to the reading on the scale.
By applying Newton's second law,
[tex]\sum F = ma[/tex]
where
[tex]\sum F = N-W[/tex] is the net force on the person
m is its mass
a is the acceleration
Here we are told that the elevator moves at constant velocity: this means that the acceleration is zero,
[tex]a=0[/tex]
Therefore, the equation becomes
[tex]N-W=0\\N=W=600 N[/tex]
So the reading on the scale is 600 N.
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