Answer:
The sound intensity level 300 m from the siren is [tex]2.77 \times 10^{-3} W/m^2[/tex]
Explanation:
Intensity at given distance is given by
[tex]I=\frac{P}{A} =\frac{P}{\pi d^2} =\frac{C}{d^2} \\[/tex]
sound intensity at 50 m is
[tex]I_{50}=\frac{C}{50^2} ........(1)[/tex]
Sound intensity at 300 m is
[tex]I_{300}=\frac{C}{300^2} ........(2)\\[/tex]
solving equation 1 and 2, we get
[tex]I_{50}\times 50^2=I_{300}\times 300^2\\0.1\times 50^2=I_{300}\times 300^2\\I_{300}=2.77 \times 10^{-3} W/m^2[/tex]
The sound intensity level 300 m from the siren is [tex]2.77 \times 10^{-3} W/m^2[/tex]
