Answer:
42.8153054899
Explanation:
[tex]m_e[/tex] = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]
[tex]m_p[/tex] = Mass of proton = [tex]1.67\times 10^{-27}\ kg[/tex]
[tex]v_e[/tex] = Velocity of electron
[tex]v_p[/tex] = Velocity of proton
Here the kinetic energy of the system is conserved so
[tex]\dfrac{1}{2}m_ev_e^2=\dfrac{1}{2}m_pv_p^2\\\Rightarrow \dfrac{v_e}{v_p}=\sqrt{\dfrac{m_p}{m_e}}\\\Rightarrow \dfrac{v_e}{v_p}=\sqrt{\dfrac{1.67\times 10^{-27}}{9.11\times 10^{-31}}}\\\Rightarrow \dfrac{v_e}{v_p}=42.8153054899[/tex]
The ratio is 42.8153054899
