Answer:0
Explanation:
It is given that Q charge is uniformly distributed over hollow spherical shell of radius a
It is clear that all the charge is outside the sphere and there is no charge inside the sphere.
Consider a Gauss surface with radius [tex]r=0.5 a[/tex]
[tex]\oint E\cdot ds=\frac{q}{\epsilon _0}[/tex]
[tex]E\cdot 4\pi (0.5a)^2=\frac{0}{\epsilon _0}[/tex]
as there is no charge inside the Gaussian surface
Therefore Electric field is at r=0.5 a
