[tex]= 0.51[/tex]The mole fraction of the nitrogen gas would be as follows:
[tex]0.51[/tex]
Given that,
Amount of oxygen gas in a mixture [tex]= 88g[/tex]
Amount of Nitrogen gas in a mixture [tex]= 88g[/tex]
Amount of Nitrogen Dioxide gas in a mixture [tex]= 12g[/tex]
Now,
The moles of [tex]O_{2}[/tex] [tex]= 88/32[/tex]
[tex]= 2.75 moles[/tex]
The moles of [tex]N_{2}[/tex] [tex]= 88/28[/tex]
[tex]= 3.14[/tex] moles
The moles of:
[tex]NO_{2} = 12/46\\= 0.261[/tex]
So,
The total moles [tex]= 2.75 + 3.14 + 0.261[/tex]
[tex]= 6.151 moles[/tex]
∵ Mole fraction of [tex]N_{2} =[/tex] No. of [tex]N_{2}[/tex] moles/Total moles
[tex]= 3.14/6.151[/tex]
[tex]= 0.51[/tex]
Thus, [tex]0.51[/tex] is the correct answer.
Learn more about "Mole Fraction" here:
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