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Initially, a 1.50-liter compressible container of 0.35 moles of a gas exerts a pressure of 740 millimeters of mercury at a temperature of 275 Kelvin. What is the pressure when the container is compressed to 0.50 liters, the moles of gas reduces to 0.20 moles, and the temperature changes to 32 degrees Celsius?

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Answer:

10 atm is the new pressure

Explanation:

Let's verify the pressure by the Ideal Gases Law for the two situations:

P . V = n . R .T

Pressure . 0.5L = 0.2 mol . 0.082L.atm/mol.K . 305K

Pressure = (0.2 mol . 0.082L.atm/mol.K . 305K) / 0.5 L

Pressure = 10 atm

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