Respuesta :

Answer:

V NH3 = 304.334 L

Explanation:

  • 1 mol ≡ 6.02 E23 molecules

⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)

⇒ mole NH3 = 12.454 mol

assuming ideal gas:

  • PV = RTn

STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

⇒ V NH3 = RTn/P

⇒ V NH3 = ((0.082 atm.L/K.mol)×(298 K)×(12.454 mol))/(1 atm)

⇒ V NH3 = 304.334 L

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