Answer:
The velocity of the tennis ball after the collision is 4.8 m/s downward.
Explanation:
When a basketball collides with tennis ball, the collision is perfectly elastic.
From the law of conservation of linear momentum, and considering opposite direction of two balls
m₁u₁ - m₂u₂ = m₁v₁ - m₂v₂
where;
m₁ is the mass of the tennis ball = 8.01 kg
u₁ is the initial velocity of the tennis ball = 5 m/s
m₂ is the mass of the basketball = 0.8 kg
u₂ is the initial velocity of the basketball = 5 m/s
v₁ is the final velocity of the tennis ball after collision = ?
v₂ is the final velocity of the basketball after collision = 3 m/s
m₁u₁ - m₂u₂ = m₁v₁ - m₂v₂
(8.01*5) -(0.8*5) = (8.01* v₁) - (0.8*3)
40.05 - 4 = 8.01v₁ - 2.4
36.05 +2.4 = 8.01v₁
38.45 = 8.01v₁
v₁ = 38.45/8.01
v₁ = 4.8 m/s
The positive sign, indicates downward velocity.
Therefore, the velocity of the tennis ball after the collision is 4.8 m/s downward.
