3 field goals and 5 touchdowns were made by the team.
Step-by-step explanation:
Given,
Number of times football team scored = 8
Worth of points scored = 44 points
Each touchdown worth = 7 points
Each field goal worth = 3 points
Let,
x be the number of times touchdown was made
y be the number of times field goal was made
x+y=8 Eqn 1
7x+3y=44 Eqn 2
Multiplying Eqn 1 by 7
[tex]7(x+y=8)\\7x+7y=56\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 2 from Eqn 3
[tex](7x+7y)-(7x+3y)=56-44\\7x+7y-7x-3y=12\\4y=12[/tex]
Dividing both sides by 4
[tex]\frac{4y}{4}=\frac{12}{4}\\y=3[/tex]
Putting y=3 in Eqn 1
[tex]x+3=8\\x=8-3\\x=5[/tex]
3 field goals and 5 touchdowns were made by the team.
Keywords: linear equation, elimination method
Learn more about elimination method at:
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