Answer: d. 8.25 m/s
Explanation:
We are given that Current= 5 m/s in j direction
Velocity= 8 m/s i + 3 m/s j
Now, we have to find Jada's speed with respect to the water.
First we find Jada's velocity with respect to water
v= (8 i + 3 j) - (5 j)
v= 8i - 2 j
To find the speed, we take the magnitude of this velocity vector we have
|v|= [tex]\sqrt{(8)^2+(-2)^2}[/tex]
|v|= [tex]\sqrt{68}[/tex] = 8.246 m/s
which comes out to be around = 8.25 m/s
So option d is correct.