Answer:
15 nickels.
8 dimes.
Step-by-step explanation:
Let be "n" the number of nickels in the jar and "d" the number of dimes in the jar.
Set up a System of equations using the information given in the exercise:
[tex]\left \{ {{n+d=23} \atop {0.05n+0.10d=1.55}} \right.[/tex]
You can use the Elimination method to solve the System of equations:
1. You need to multiply the first equation by -0.10
2. Now you must add the equations.
3. Solve for "n".
Then:
[tex]\left \{ {{-0.10n-0.10d=-2.3} \atop {0.05n+0.10d=1.55}} \right.\\..................................\\-0.05n=-0.75\\\\n=\frac{-0.75}{-0.05}\\\\n=15[/tex]
4. Finally you must substitute the value of "n" into any original equation and solve for "d" in order to find its value.
Then, you get:
[tex]15+d=23\\\\d=23-15\\\\d=8[/tex]
