Answer:
Wave speed on the spring is 40 m/s
Explanation:
Frequency for standing wave mode of an open- open tube is given by
[tex]f_{} =\frac{v}{2L}[/tex]
where v is the velocity, L =1 m is the length
wave speed on the spring is
[tex]v =2fL\\v=2\times 20\times 1\\v=40 m/s[/tex]