Respuesta :
The given question is incomplete. The complete question is as follows.
Two new particles, which have identical positive charge [tex]q_{3}[/tex], are placed the same 0.0509 meters apart, and the force between them is measured to be the same as that between the original particles, 97.2 N. What is [tex]q_{3}[/tex]?
Explanation:
Expression for electric force between two charged particles [tex]q_{1}[/tex] and [tex]q_{2}[/tex] are as follows.
F = [tex]k \times \frac{q_{1}q_{2}}{d^{2}}[/tex]
here, [tex]q_{1} = q_{2} = q_{3}[/tex]
Therefore, expression will be as follows.
F = [tex]k \frac{q_{3}q_{3}}{d^{2}}[/tex]
= [tex]k \frac{q_{3}^{2}}{d^{2}}[/tex]
[tex]q_{3} = d \times \sqrt{\frac{F}{k}}[/tex]
= [tex]0.0509 \times \sqrt{(\frac{97.2}{(9 \times 10^{9})}[/tex]
= [tex]5.29 \times 10^{-6} C[/tex]
or, = [tex]5.29 \mu C[/tex]
Thus, we can conclude that the value of [tex]q_{3}[/tex] is [tex]5.29 \mu C[/tex].
