Respuesta :
Answer: 0.499mol
Explanation:
4NH3 + 5O2 -> 4NO + 6H2O
Molar Mass of NH3 = 14 + 3 = 17g/mol
Mass conc. Of NH3 = 6.78g
n = Mass conc. / molar Mass
n = 6.78 / 17 = 0.399mol
From the equation,
4moles of NH3 required 5moles of O2.
Therefore, 0.399mol of NH3 will require Xmole of O2. i.e
Xmol of O2 = (0.399 x 5) / 4 = 0.499mol
The number of moles of oxygen required is 0.499mol.
Given,
Molar Mass of [tex]NH_3 = 14 + 3 = 17g/mol[/tex]
Mass concentration of [tex]NH_3=6.78 g[/tex]
The formula for number of moles :
[tex]n=\frac{Given mass}{Molar mass}[/tex]
We can calculate the moles by using the above formula,
n = 6.78 / 17 = 0.399mol
From the equation,
4moles of [tex]NH_3[/tex] required 5moles of [tex]O_2[/tex].
Therefore, 0.399mol of [tex]NH_3[/tex] required x moles of [tex]O_2[/tex].
X mol of [tex]O_2 = (0.399\times 5) / 4 = 0.499mol[/tex]
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