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An experimenter finds that standing waves on a string fixed at both ends occur at 24 Hz and 32 Hz, but at no frequencies in between.
a. What is the fundamental frequency?
b. Draw the standing-wave pattern for the string at 32 Hz.

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Answer:

8 Hz

Explanation:

The frequency of a wave when both ends are fixed is given by

[tex]f=n\dfrac{v}{2L}[/tex]

where,

n = 1, 2, 3, 4.............

v = Velocity of sound in air

L = Length of tube

The difference between two frequencies is given by

[tex]f_{(n+1)}-f_n=(n+1)f-nf=f[/tex]

So,

[tex]f_1=32-24=8\ Hz[/tex]

The fundamental frequency is 8 Hz

[tex]n=\dfrac{f_n}{f_1}=\dfrac{32}{8}=4[/tex]

Ver imagen boffeemadrid

The fundamental frequency is 8Hz

Frequency modes:

The frequency modes of a wave in a string with both ends are fixed is given by

[tex]f_n=\frac{nv}{2L}[/tex]

where,

n = 1, 2, 3, 4.............

v is the velocity of the wave

L is the length of the string

Now, n = 1 gives fundamental frequency

The frequencies for n>1 are called overtones.

The difference between two successive overtones is:

[tex]f_{n+1}-f_n=\frac{v}{2L}=f[/tex]

So from the question we get:

[tex]f=(32-24)Hz\\\\f=8Hz[/tex]is the fundamental frequency

Learn more about fundamental frequency:

https://brainly.com/question/25694821?referrer=searchResults

Ver imagen ConcepcionPetillo