Answer:
Q = 43.4 nC
Explanation:
According to the Gauss Law, the net electric flux through a closed surface, is equal to the charge enclosed by this surface, divided by the permitivitty of the free space, as follows:
Flux = Q/ε₀
If we know that the net electric flux through a cubic box with sides that are 22 cm. long, is 4.9*10³ N*m²/C, we can find the enclosed charge, defining a gaussian surface identical to this cube, as follows:
Qenc = 4.9*10³ N*m²/C * 8.85*10⁻¹² C²/N*m² = 43.4*10⁻⁹ C = 43.4 nC
The charge Q enclosed by the box is; Q_enc = 43.4 nC
According to the Gauss Law, the formula for the net electric flux through a closed surface is;
Ф = Q/ε₀
where;
Ф is net electric flux
ε₀ = 8.85 × 10⁻¹² C²/N.m²
Q is charge
Now, since the net electric flux through a cubic box with sides that are 22 cm. long, is 4.9 × 10³ N.m²/C, it means that we can find the enclosed charge, defining a gaussian surface identical to this cube from:
Q_enc = 4.9 × 10³ N.m²/C 8.85 × 10⁻¹² C²/N*m²
Q_enc = 43.4 × 10⁻⁹ C
Q_enc = 43.4 nC
Read more about net electric flux at; https://brainly.com/question/14952197
