Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz
Explanation:
We are given that,
Length of tub= 1.5 m
Width of tub= 0.75 m
Sound speed= 343 m/s
Now, we are also given shower is closed.
So, frequency is given as:
f= [tex]m* \frac{v}{2L}[/tex]
For length axis
Put v= 343 m/s, m=1 and L=1.5 m
f= 1 * [tex]\frac{343}{2*1.5}[/tex]
f= 114.3 Hz
For next resonant frequency, m=2
f= 2* [tex]\frac{343}{2*1.5}[/tex]
f= 228.67
For width axis
Put v= 343 m/s, m=1 and L= 0.75 m
f= 1* [tex]\frac{343}{2*0.75}[/tex]
f= 228.67 Hz
For next frequency, m=2
f= 2* [tex]\frac{343}{2*0.75}[/tex]
f= 457.34 Hz