Respuesta :
Answer:
1/4
Step-by-step explanation:
Given that
The probability that Deva will be late for school tomorrow and Emilio will be late for school tomorrow is [tex]\frac{3}{16}[/tex]
the probability that Deva will be late for school tomorrow and Emilio will not be late for school tomorrow is [tex]\frac{9}{16}[/tex]
Also given that Deva and Emily are independent of being late
Let A = Deva late and B = Emillio late
P(AB) = [tex]\frac{3}{16}[/tex]
P(AB') = [tex]\frac{9}{16}[/tex]
We have P(AB) = P(A) P(B)
and P(AB') = P(A) P(B')
Dividing P(B)/P(B') = 1/3
Since B and B' have probability adding to 1
[tex]\frac{P(B)}{P(B)+P(B')} =\frac{1}{3+1} =\frac{1}{4}[/tex]
Use this in
P(AB) = P(A)P(B) = [tex]\frac{3}{16}[/tex]
P(A) = [tex]\frac{3}{4}[/tex]
required probability = P(A') = 1-P(A)
=[tex]\frac{1}{4}[/tex]
