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A rectangular block floats in pure water with 0.5 inch above the surface and 1.5 inches below the surface. When placed in an aqueous solution, the block of material floats with 1 inch below the surface. Estimate the density of the block and the solution

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boffeemadrid

Answer:

750 kg/m³

1500 kg/m³

Explanation:

SG = Specific gravity of water

Specific gravity of block

[tex]\dfrac{\text{Block volume below}}{\text{Total block volume}}\times SG=\dfrac{1.5}{1.5+0.5}1=0.75[/tex]

Density of block

[tex]\rho_b=0.75\times 1000\\\Rightarrow \rho_b=750\ kg/m^3[/tex]

Density of block is 750 kg/m³

Specific gravity of solution

[tex]\dfrac{\text{Total block volume}}{\text{Block volume below}}\times SG=\dfrac{2}{1}0.75=1.5[/tex]

Density of solution

[tex]\rho_s=1.5\times 1000\\\Rightarrow \rho_s=1500\ kg/m^3[/tex]

Density of block is 1500 kg/m³

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