Answer:
[tex]14.96\times 10^{-6}C[/tex]
Explanation:
We are given that
Electric field=E=[tex]22.1 N/C[/tex]
Distance , r=78 m
Coulomb constant=k=[tex]8.98755\times 10^9Nm^2/C^2[/tex]
We have to find the charge.
We know that electric field
[tex]E=\frac{Kq}{r^2}[/tex]
Substitute the values
[tex]22.1=\frac{8.98755\times 10^9\times q}{(78)^2}[/tex]
[tex]q=\frac{22.1\times (78)^2}{8.98755\times 10^9}[/tex]
[tex]q=14.96\times 10^{-6}C[/tex]
Hence,the charge=[tex]14.96\times 10^{-6}C[/tex]
