Answer:
Possible values of d are 1m, 3m, 5m...
Explanation:
The wavelength of the sound wave is given by
[tex]\lambda=\frac{v}{f}\\\lambda=\frac{340}{170}\\\lambda=2 m[/tex]
Condition for destructive interference is given by
[tex]\Delta d=(m+\frac{1}{2} )\lambda[/tex] where m= 0,1,2,3,...
when m=0, we will get minimum destructive interference. i.e
[tex]\Delta d_{1}=(m+\frac{1}{2} )\lambda=(0+\frac{1}{2} )2=1m\\[/tex]
when m=1,
[tex]\Delta d_{2}=(m+\frac{1}{2} )\lambda=(1+\frac{1}{2} )2=3m[/tex]
when m=2
[tex]\Delta d_{3}=(m+\frac{1}{2} )\lambda=(2+\frac{1}{2} )2=5m[/tex]
