contestada

Two loudspeakers in a 20°C room emit 686 Hz sound waves along the x-axis. What is the smallest distance between the speakers for which the interference of the sound waves is destructive?

Respuesta :

boffeemadrid

Answer:

0.25 m

Explanation:

v = Speed of sound in air at 20°C  = 343 m/s

f = Frequency = 686 Hz

Wavelength is given by

[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{686}\\\Rightarrow \lambda=0.5\ m[/tex]

The wavelength is 0.5 m

Path difference for destructive interference

[tex]\Delta x=\dfrac{\lambda}{2}\\\Rightarrow \Delta x=\dfrac{0.5}{2}\\\Rightarrow \Delta x=0.25\ m[/tex]

The required distance is 0.25 m