Respuesta :
Answer:
E_1 = E_2 > E_3
Explanation:
Given:
- Charged sphere 1 has a radius = R/2
- Charged sphere 2 has a radius = R
- Charged sphere 3 has a radius = 2R
- All charged non conducting spheres have equal Q charge
Find:
- Rank electric field created by each sphere at distance r = R. Greatest to lowest.
Solution:
- The electric field of a non-conducting uniform distributed charge sphere @ r greater than or equal to radius of the sphere is given by:
r >= radius
E = k*Q / r^2
For spheres 1 and 2, the distance r = R is either on surface or outside the sphere. So,
E_1 = k*Q / R^2
E_2 = k*Q / R^2
Hence, both sphere 1 and 2 have equal Electric field at r = R.
- The electric field of a non-conducting uniform distributed charge sphere @ r less than to radius of the sphere is given by:
r < radius
E = k*Q*r / (Radius)^3
For sphere 3, the distance r = R is within the sphere. So,
E_3 = k*Q*R / 8R^3
E_3 = k*Q/ 8R^2
Hence, sphere 3 has less electric field at point r = R.
So the order is: E_1 = E_2 > E_3
