Answer:
The answer to the question is
The period of the blinker of the other car = 0.809 s
Explanation:
To solve this we list out the variables thus
Period of the student turn signal = 0.85 s, Period of the other car signal = T
In 17 seconds the two cars signal are in sync again
Therefore the frequency of the students car signal = 1/0.85 = 1.176 Hz and the frequency of the other car signal is 1/T however is 17 seconds the other car is ahead by one cycle thus
Therefore
17/T - 17/0.85 = 1
Which gives 17/T = 1 + 17/0.85 = 17.85/0.85 =
Multiplying both sides by T we have
17 = T×17.85/0.85
Therefore T = 17×0.85/17.85 = 0.809 s
The period of the blinker of the other car is 0.809 s
