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About 75 g of blood is pumped from a person's heart into the aorta during each heartbeat. The blood starts at rest with respect to the body and has a speed of about 1.0 m/s in the aorta. If the pumping takes 0.15 s, what is the magnitude of the average force exerted by the heart on the blood?

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KvngDami

Answer:

Explanation:

F = m (vf - vi)/t

F = force  

m = mass  = 75g = 0.075kg

vf = final velocity  = 1.0 m/s

vi = initial velocity  = 0(since the body is staring from rest)

t = time = 0.15s

F = [tex]\frac{0.075(1-0)}{0.15}[/tex]

F = 0.5 N

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