Suppose 3 quarts of a solution that is 22% antifreeze is mixed with 2 quarts of a solution that is 85% antifreeze.
(a) How many quarts of antifreeze are in the resulting mixture?
(b) What percentage of the resulting mixture is antifreeze?

Respuesta :

Answer:

Part a) 2.36 quarts

Part b) 47.2%

Step-by-step explanation:

Let

x ---> percentage of the resulting mixture that is antifreeze

Remember that

[tex]22\%=22/100=0.22[/tex]

[tex]85\%=85/100=0.85[/tex]

we know that

3 quarts of a solution multiplied by 0.22 (percentage in decimal form) plus  2 quarts of a solution multiplied by 0.85 (percentage in decimal form), must be equal to 5 quarts of a solution multiplied by x (percentage of the resulting mixture)

so

The linear equation that represent this situation is

[tex]3(0.22)+2(0.85)=(3+2)x[/tex]

solve for x

[tex]0.66+1.7=5x\\5x=2.36\\x=0.472[/tex]

Convert to percentage

[tex]0.472*100=47.2\%[/tex]

therefore

The percentage of the resulting mixture that is antifreeze is 47.2%

To find out how many quarts of antifreeze are in the resulting mixture, multiply the total quarts of the resulting mixture by the percentage in decimal form

[tex]5(0.472)=2.36\ quarts[/tex]

The number of quarts of antifreeze in the resulting mixture is 0.472

How to solve equation

let

  • Quarts of antifreeze are in the resulting mixture = x

The equation

3(22%) + 2(85%) = x(3+2)

3(0.22) + 2(0.85) = x(5)

0.66 + 1.7 = 5x

2.36 = 5x

  • divide both sides by 5

x = 2.36/5

= 0.472

Percentage of the resulting mixture is antifreeze = 0.472 × 100

= 47.2%

The percentage of the resulting mixture is antifreeze is 47.2%

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