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Consider the reaction, 2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g) When D is decreasing at 0.15 mol/Ls, how quickly is E decreasing? Give your answer to 3 decimal places.

Respuesta :

Answer:

0.023 mol/(L*s).

Explanation:

Equation of the reaction:

2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g)

Using stoichiometry, 2 moles of D reacts with 3 moles of E and 1 mole of F to give the above products.

1 mole of D will react with 3/2 moles of E.

Delta[D]/delta t = 0.15 mol/L.s

Delta[E]/delta t = (3/2) * 0.15 =

= 0.023 mol/(L*s).

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