Answer:
Explanation:
Given
Length of tendon [tex]L=20\ cm[/tex]
Area of cross-section [tex]A=110\ mm^2[/tex]
Density of tendon [tex]\rho =1100\ kg/m^3[/tex]
Tension in the string [tex]T=500\ N[/tex]
Linear mass Density [tex]\mu =\frac{m}{L}[/tex]
[tex]\mu =\frac{\rho AL}{L}[/tex]
[tex]\mu =\rho \cdot A[/tex]
Fundamental Resonant frequency is given by
[tex]f=\frac{1}{2 L}\sqrt{\frac{T}{\rho A}}[/tex]
[tex]f=\frac{1}{2\times 0.2}\sqrt{\frac{500}{1100\times 110\times 10^{-6}}}[/tex]
[tex]f=160.70\ Hz[/tex]