Select the correct answer from each drop-down menu.

In the figure, CD = EF and AB = CE. Complete the statements to prove that AB = DF.

CD + DE = EF + DE by the ___ Property of Equality.

A. Addition
B. Subtraction
C. Substitution
D. Transitive

CE = CD + DE and DF = EF + DE by_____.

A. Addition
B. Subtraction
C. Segment Addition
D. Transitive

CE = DF by the_____Property of Equality.

A. Addition
B. Subtraction
C. Substitution
D. Transitive

Given, AB = CE and CE = DF implies AB = DF by the____Property of Equality.

A. Addition
B. Subtraction
C. Substitution
D. Transitive

Select the correct answer from each dropdown menu In the figure CD EF and AB CE Complete the statements to prove that AB DF CD DE EF DE by the Property of Equal class=

Respuesta :

In the figure, CD = EF and AB = CE

To prove that AB = DF:

Step 1:  

Given CD = EF, so we can substitute EF instead of CD.

CD + DE = EF + DE

by the Substitution Property of Equality.

Here, Option C is the correct answer.

Step 2:  

CD + DE = CE and

EF + DE = DF

by Segment Addition.

Here, Option C is the correct answer.

Step 3:  

From step 1, CD + DE = EF + DE

From step 2, CE = DF

So, CE = DF by the Transitive Property of Equality.

Here, Option D is the correct answer.

Step 4:  

Given AB = CE and CE = DF

⇒ AB = DF

by the Transitive Property of Equality.

Here, Option D is the correct answer.

Hence proved.

Answer:

A. Addition  

B.  segment addition

C. Transitive  

D. Transitive  

Step-by-step explanation:

CD + DE = EF + DE by the  Addition  Property of Equality.

CE = CD + DE and DF = EF + DE by  segment addition

CE = DF by the  Transitive  Property of Equality.

Given, AB = CE and CE = DF implies AB = DF by the  Transitive  Property of Equality.

Correct for plato, I just took the test ;)