Answer:
1,-6
Step-by-step explanation:
Given quadratic equation is [tex]\[3x^{2}+15x=18\][/tex]
This can be represented as [tex]\[3x^{2}+15x-18=0\][/tex]
This is of the form [tex]\[ax^{2}+bx+c=0\][/tex]
where a=3,b=15 and c = -18
The roots of this equation are given by:
[tex]\[\frac{-15\pm \sqrt{15^{2}-4*3*(-18)}}{2*3}\][/tex]
= [tex]\[\frac{-15\pm \sqrt{225+216}}{6}\][/tex]
= [tex]\[\frac{-15\pm \sqrt{441}}{6}\][/tex]
= [tex]\[\frac{-15\pm 21}{6}\][/tex]
= 1, -6
