At the conclusion of a soccer game whose two teams each included 11 players, each player on the winning team "gave five" to (slapped hands with) each player on the losing team. Each player on the winning team also gave five to each other player on the winning team. How many fives were given?

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aojsoft aojsoft · Answer 1 · 2020-02-08T12:17:53+01:00

Answer:

231 fives were given.

Step-by-step explanation:

For each player in the winning team to give five to each player in the losing team, it implies:

==> 11 x 11 fives = 121 fives.

For each player in the winning team to each other five, it will exclude 'self'. - That is, each player will give 10 fives each. Hence:

==> 11 * 10 fives = 110 fives

Therefore,

We have: 121 + 110 fives = 231 fives given.

NB: Each player in the winning will not give himself a five. Hence, each player will give five to other 10 players in the team.

But, for the losing team, each player in the winning team will give 11 fives. That is, a five to each player in the losing team!