Answer:
part(a) 151 m
part(b) 1.073 m/s2
part(c) 16.7 secs
Explanation:Firstly the person applied brakes 0.5 secs after seeing the red light hence the distance traveled during this time is
d=v*t
d=18*0.5
d=9m
For part (a)
I have corrected this question and now
The person was 160m from the intersection before applying the brakes as he traveled 9m before the brakes
He is now 151 m from intersection as
s=160-9
s= 151 m
part (b)
As it is given that velocity of the car is 0 at the intersection so we use this information in kinematic equation
[tex]v^2=u^2+2as[/tex]
here u=18m/s and s=151
[tex]0=18^2+2a*151\\302a=-324\\a=-1.073 m/s^2[/tex]
To calculate time we can use the acceleration equation
[tex]a=\frac{v-u}{t} \\t=\frac{v-u}{a}\\t=18/1.073\\t=16.77 secs[/tex]