[tex]98 \times m \text { joules }[/tex] is the potential energy of the ball as it is half way through the fall, 20 meters high.
Explanation:
Given data:
Height of the fall = 20 m
Given that the body is half-way through the fall, it is at above the ground 10 m
[tex]\frac{1}{2} \times 20=10 \mathrm{m}[/tex]
We need to find its potential energy (P.E)
Energy due to the body’s position is referred as potential energy. It means the energy when body is at rest. It can be expressed as below,
[tex]\text { Potential energy }(P . E)=m \times g \times h[/tex]
Where
,
m – The body’s mass
g - Acceleration due to gravity [tex]\left(9.8 m / s^{2}\right)[/tex]
h - Height of the body
By substituting the given values, we get
[tex]Potential energy =m \times 9.8 \times 10=98 \times m\ joule[/tex]
Since the mass is not provided, just kept it. By knowing the mass values, we can find the potential energy.
