Answer:
Explanation:
The₍compound of unknown metal is XBr₃
we shall calculate how much of X reacts with 3 x 80 g of Br . It will be equal to atomic weight of X . .
4.760 x 10⁻² mol of Br = 4.760 x 10⁻² x 80 gram of Br
= 3.808g
So 4.735 g of sample contains 3.808 g of Br and (4.735 - 3.808 ) = .927 g of metal
3.808 g of Br reacts with .927 g of metal X
3 X 80 g of Br will react with ( .927 / 3.808) x 3 x 80 g of metal X
= 58.42 g of X
So atomic weight = 58 .42 g
